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Is reason for climate change correct?



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29-08-2019 22:02
tmiddlesProfile picture★★★★☆
(1142)
Into the Night wrote:
I don't claim anything. YOU are the only one claiming anything.


So what would you estimate you're radiating right now?
29-08-2019 23:15
Into the Night
★★★★★
(9286)
tmiddles wrote:
Into the Night wrote:
I don't claim anything. YOU are the only one claiming anything.


So what would you estimate you're radiating right now?

Unknown.


The Parrot Killer
29-08-2019 23:17
tmiddlesProfile picture★★★★☆
(1142)
Into the Night wrote:
tmiddles wrote:
Into the Night wrote:
I don't claim anything. YOU are the only one claiming anything.


So what would you estimate you're radiating right now?

Unknown.


Do you know how to use the Stefan-Boltzmann equation? Would you like a lesson?
29-08-2019 23:23
Into the Night
★★★★★
(9286)
tmiddles wrote:
Into the Night wrote:
tmiddles wrote:
Into the Night wrote:
I don't claim anything. YOU are the only one claiming anything.


So what would you estimate you're radiating right now?

Unknown.


Do you know how to use the Stefan-Boltzmann equation? Would you like a lesson?


What part of radiance = SBconstant * emissivity * temperature ^ 4
eludes you?


The Parrot Killer
29-08-2019 23:26
tmiddlesProfile picture★★★★☆
(1142)
Into the Night wrote:
What part of radiance = SBconstant * emissivity * temperature ^ 4
eludes you?


Let's see. Did I do it right?:

For: Temp ~ 91F/33C/306K, Surface area ~ 1.5m2 of skin, Emissivity ~ 0.97

Stefan-Boltzmann equation:___P(out)=σeA*(T1^4)
(5.67×10−8J/s⋅m2⋅K4)(0.97)(1.50m2)306K^4=-723W
29-08-2019 23:48
Into the Night
★★★★★
(9286)
tmiddles wrote:
Into the Night wrote:
What part of radiance = SBconstant * emissivity * temperature ^ 4
eludes you?


Let's see. Did I do it right?:

For: Temp ~ 91F/33C/306K, Surface area ~ 1.5m2 of skin, Emissivity ~ 0.97

Stefan-Boltzmann equation:___P(out)=σeA*(T1^4)
(5.67×10−8J/s⋅m2⋅K4)(0.97)(1.50m2)306K^4=-723W


Math error. It is +723W, not -723W. Otherwise, it looks correct for the randU numbers you used. Of course, since you used randU numbers, the answer is also randU.

Emissivity is unknown. You simply chose a number out of thick air.
The surface area of the the subject is unknown. You simply chose a number out of thick air.
So the value of 723W is also just randU out of thick air.


The Parrot Killer
30-08-2019 00:25
tmiddlesProfile picture★★★★☆
(1142)
Into the Night wrote:
tmiddles wrote:
...723W


Math error. It is +723W, not -723W. Otherwise, it looks correct for the randU numbers you used. Of course, since you used randU numbers, the answer is also randU.


It's as much randU as saying a person who is 5' 8" and 150lbs though right? It's in a normal range. All the values used are.

So that's a 723 watt loss of energy from emitted radiance correct?

Again this was from the textbook:
tmiddles wrote:
University Physics Volume 2
1.6 Mechanisms of Heat Transfer
"EXAMPLE 1.13
Calculating the Net Heat Transfer of a Person
What is the rate of heat transfer by radiation of an unclothed person standing in a dark room whose ambient temperature is 22.0°C? The person has a normal skin temperature of 33.0°C and a surface area of 1.50m2. The emissivity of skin is 0.97 in the infrared, the part of the spectrum where the radiation takes place
30-08-2019 02:02
Into the Night
★★★★★
(9286)
tmiddles wrote:
Into the Night wrote:
tmiddles wrote:
...723W


Math error. It is +723W, not -723W. Otherwise, it looks correct for the randU numbers you used. Of course, since you used randU numbers, the answer is also randU.


It's as much randU as saying a person who is 5' 8" and 150lbs though right? It's in a normal range. All the values used are.

So that's a 723 watt loss of energy from emitted radiance correct?

With the understanding that the 723W is a randU number, yes.
tmiddles wrote:
Again this was from the textbook:
tmiddles wrote:
University Physics Volume 2
1.6 Mechanisms of Heat Transfer
"EXAMPLE 1.13
Calculating the Net Heat Transfer of a Person
What is the rate of heat transfer by radiation of an unclothed person standing in a dark room whose ambient temperature is 22.0°C? The person has a normal skin temperature of 33.0°C and a surface area of 1.50m2. The emissivity of skin is 0.97 in the infrared, the part of the spectrum where the radiation takes place


This book is in error.

* Emissivity has no frequency.
* Radiance doesn't take place in a single band.
* There is no such thing as 'net heat'. Heat only flows in one direction.
* There is no such thing as 'heat transfer'. Heat IS transfer of thermal energy.
* The emissivity of human skin is unknown.
* Conductive and convective heat are being utterly ignored.
* There is no such thing as 'greenhouse effect' in the atmosphere. No gas or vapor has the capability to warm the Earth.
* You cannot create energy out of nothing.
* You cannot make heat flow from cold to hot.
* You cannot decrease entropy in any system.
* You cannot hold or trap heat.
* You cannot trap thermal energy. There is always heat. It always flows in one direction.
* You cannot trap light.
* You cannot reduce the radiance of Earth and increase its temperature at the same time.

This book ignores all of these things. It denies the 1st and 2nd laws of thermodynamics and the Stefan-Boltzmann law.


The Parrot Killer
Edited on 30-08-2019 02:07
30-08-2019 03:14
tmiddlesProfile picture★★★★☆
(1142)
Into the Night wrote:
With the understanding that the 723W is a randU number, yes.

Thank you! Response moved here: NET THERMAL RADIATION : You in a room as a reference.
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