# A particle moves along a straight line OX. At a time t (in seconds) the distance x (in metre) of the particle is given by x=40+12t−t3. How long would the particle travel before coming to rest ?

24m

40m

56m

16m

## The correct Answer is:D

## x=40+12t−t3

v=dxdt=12−3t2

final velocity v = 0

rArr 3t2=12⇒t=2sec<br> therefore x = 40 + 12 xx 2 - (2)^3 = 56m<br> x = 56-40

= 16m

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