Physics of climate change question25-11-2017 01:13 | |
Skaha☆☆☆☆☆ (2) |
For photons to escape the atmosphere they need to reach around 5km in altitude. If we double the co2, the atmosphere gets thicker and the altitude at which photons escape is increased. Energy out = sigma * T^4 where "T" is emission temperature. At higher altitudes "T" is lower, therefore the energy that escapes is lower, thus a warmer planet. My question is: If the density of co2 doubles, wouldn't the surface area of the atmosphere (4*pi*r^2) also increase? And with greater surface area, wouldn't the amount of photons emitted also increase? Counteracting the warming effect? I would appreciate it if someone could answer this question because it is really bugging me. Sincerely, Havard |
25-11-2017 02:21 | |
litesong★★★★★ (2297) |
Skaha wrote: Counteracting the warming effect? I would appreciate it if someone could answer this question because it is really bugging me. Sincerely, HavardSince this webcyst was started by AGW denier liar whiners, an AGW denier liar whiner will "come forth" (like Lazarus) to confirm your idea & anti-AGW denier liar whining will start all over.... anew. |
25-11-2017 02:56 | |
Skaha☆☆☆☆☆ (2) |
litesong wrote:Since this webcyst was started by AGW denier liar whiners, an AGW denier liar whiner will "come forth" (like Lazarus) to confirm your idea & anti-AGW denier liar whining will start all over.... anew.[/quote It's not my theory, and I doubt climate scientists missed this in their calculations, but I found it strange that no one has mentioned it in their reports. (Of those I've read) I thought the consensus on this page was in support of human caused global warming. |
25-11-2017 03:59 | |
Into the Night★★★★★ (22614) |
Skaha wrote: What you are describing is almost the Stefan-Boltzmann law. That law states: radiance = SBconstant * emissivity * temperature ^ 4. The SBconstant is a constant of nature. The emissivity constant is a measured constant. It describes how well the surface absorbs and emits light, as opposed to reflecting or scattering it. Temperature is in Kelvin. Radiance is in watts/square meter. While the colder air does radiate less because it's colder, it also radiates less because the air is so thin there isn't much 'surface area' to radiate from. Gases are kind of funny in calculating effective radiating 'surface area'. They do have one though. This, however, is ignoring the Earth surface itself, which is the warmest of all, the densest material also, and therefore radiates the most energy in the form of light. Most of the radiance of the Earth is from the surface, not the atmosphere. Skaha wrote: No. The total material on Earth stays the same. We do not get CO2 from space. We get it from other materials already on the Earth. Adding CO2 to the atmosphere by burning something takes away from the O2 in the atmosphere. Burning something takes the carbon from the surface of the Earth (or under it), and combines it with the oxygen in the atmosphere. The result is no more material is added to Earth. It just changes form. Skaha wrote: If you COULD somehow add material on the Earth in the form of adding gasses to the atmosphere from space, yes, more photons would radiate, but the Earth would also be absorbing more energy from the Sun by the same ratio. Skaha wrote: It could be argued that pulling carbon materials out of the ground and converting them to CO2 is adding to the atmosphere, but the other half of the carbon cycle should be considered. Plant life on Earth absorbs CO2 and manufacture carbohydrates, which is food and material for the plant. Later this is our food. The carbon is returned to solid form by this process. The other result of photosynthesis is the release of excess oxygen from the chemical reaction. Plants convert CO2 to carbohydrates and release O2. It just one big circle of life...as they say. You can find more information on these subjects from many physics textbooks, but putting it together in the form of an answer to your question is not that common. The key material you want to study is the Stefan-Boltzmann law and how it applies to all bodies. Related laws are Planck's laws. You can derive the Stefan-Boltzmann law from Planck's law. The Parrot Killer Debunked in my sig. - tmiddles Google keeps track of paranoid talk and i'm not on their list. I've been evaluated and certified. - keepit nuclear powered ships do not require nuclear fuel. - Swan While it is true that fossils do not burn it is also true that fossil fuels burn very well - Swan |
25-11-2017 04:00 | |
Into the Night★★★★★ (22614) |
Skaha wrote:litesong wrote:Since this webcyst was started by AGW denier liar whiners, an AGW denier liar whiner will "come forth" (like Lazarus) to confirm your idea & anti-AGW denier liar whining will start all over.... anew.[/quote There are those who believe in 'global warming' and those who don't here. A debate needs two or more sides. The Parrot Killer Debunked in my sig. - tmiddles Google keeps track of paranoid talk and i'm not on their list. I've been evaluated and certified. - keepit nuclear powered ships do not require nuclear fuel. - Swan While it is true that fossils do not burn it is also true that fossil fuels burn very well - Swan |
25-11-2017 06:27 | |
litesong★★★★★ (2297) |
"old sick silly sleepy sleepy sleezy slimy steenkin' filthy vile reprobate rooting (& rotting) racist pukey proud pig AGW denier liar whiner badnight" bluffed: A debate needs two or more sides.Same thing was babbled (& bluffed) by the smoking-cancer denier lobby (heartless heartland, paid by the cigarette industry), as they tried to make room for mouthy mumblings.... & more babblings. Surprise, surprise! heartless heartland is up to the plate for the oil industry, using the same tactics. |
09-02-2020 23:22 | |
CzarnyZajaczek☆☆☆☆☆ (23) |
Earth radius is roughly 6378 km, increasing radiation altitude twice from 5 km to 10 km increases radiating sphere radius by 0,0783% Surface of sphere is A = 4*π*r^2 Surface of radiating sphere with radiation at altitude 5 km: r = 6378 + 5 = 6383km A0 = 511987729 km^2 Surface of radiating sphere with radiation at altitude 10 km: r = 6378 + 10 = 6388km A1 = 512790155 km^2 this is increase of surface by ~0.16% (A1 = A0 * 1,0015672751) Edited on 09-02-2020 23:31 |
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